Troughness of basic concepts and definitions of permutations is helpful in finding the rank of given words.
Problem:in the rank o the word ' MASTER ' when all the letters of the word are arranged in all possible ways,and the resulting words are arranged alphabetically.
Solution: Given word MASTER
Alphabetical order off the letters o the word A,E,M,R,S,T
No of words starting with 'A ' = A _ _ _ _ _ = 5!
No of words starting with ' E' = E _ _ _ _ _ = 5!
No of words starting with' MAE ' = MAE _ _ _ =3!
No of words starting with ' MAR ' = MAR _ _ _ = 3!
No of words starting with ' MASE ' = MASE _ _ = 2!
No of words starting with' MASR' = MASR _ _ = The next word= MASTER =1
Thus the rank of the word MASTER = 5! + 5! + 3! + 3! + 2! + 2! +1
=2 (5!) + 2 (3!) + 2 (2!) + 1=257
