The centers of the two circles are the points P and Q. The radius of circle P is 8; the radius of circle Q is 12. Find each distance.

a) SQ b) RQ c) RT

Given PS = PR = 8 and PQ = QT = 12.
SQ = PQ – PS = 12 – 8 = 4
RQ = RS + SQ = 16 + 4 = 20
RT = RQ + QT = 20 + 12 =32
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ddavis88 said – Fri, 24 Apr 2009 18:59:07 -0000 ( Flag Edit Link )
sq=4; rq=20; rt=32 I think. Thats what chandunr got unless i did it wrong.